## Answer :

**Answer:**

x = ± 5i

**Step-by-step explanation:**

given the equation

y = x² + 25

To **solve** the equation , let y = 0 , that is

x² + 25 = 0 ( **subtract** 25 from both sides )

x² = - 25 ( take **square root** of both sides )

[tex]\sqrt{x^2}[/tex] = ± [tex]\sqrt{-25}[/tex] , that is

x = ± [tex]\sqrt{25(-1)}[/tex]

x = ± ( [tex]\sqrt{25}[/tex] × [tex]\sqrt{-1}[/tex] ) = ± 5i