## Answer :

**Answer:**

**Step-by-step explanation:**

To find the zeros of the function f(x) = 2x^2 - 8x - 24, we need to set the function equal to zero and solve for x.

2x^2 - 8x - 24 = 0

Now, we can factor the quadratic equation or use the quadratic formula to find the values of x.

Factoring:

2(x^2 - 4x - 12) = 0

2(x - 6)(x + 2) = 0

Setting each factor to zero:

x - 6 = 0 or x + 2 = 0

x = 6 or x = -2

Therefore, the smaller zero of the function f(x) = 2x^2 - 8x - 24 is x = -2.

does this help or nah

**Answer:**

**The smaller zero is -2.**

**Step-by-step explanation:**

f(x)=2x^2-8x-24

To find the zeros, **set the function equal to zero.**

0=2x^2-8x-24

Divide by 2

0=x^2-4x-12

Factor

0 = (x-6) (x+2)

**Using the zero product property**

x-6 =0 x+2 =0

x=6 x=-2

The two zeros are -2, 6

The smaller zero is -2.