Answer :

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[tex]6x+5y=7 \\ 2x-4y=-26 \ \ \ |\hbox{multiply by (-3)} \\ \\ 6x+5y=7 \\ \underline{-6x+12y=78} \ \ \ |\hbox{add the sides} \\ 5y+12y=7+78 \\ 17y=85 \ \ \ |\hbox{divide by 17} \\ y=5 \\ \\ \hbox{substitute 5 for y:} \\ 6x+5y=7 \\ 6x+5 \times 5=7 \\ 6x+25=7 \ \ \ |\hbox{subtract 25} \\ 6x=-18 \ \ \ |\hbox{divide by 6} \\ x=-3 \\ \\ \boxed{(x,y)=(-3,5)}[/tex]
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[tex]Good Luck![/tex]
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