Answer :
[tex]\frac{3}{4}(\frac{4}{5}x-2)=\frac{11}{4}\ \ \ \ \ \ |multiply\ both\ sides\ by\ 4\\\\3(\frac{4}{5}x-2)=11\\\\\frac{12}{5}x-6=11\ \ \ \ \ |add\ 6\ to\ both\ sides\\\\\frac{12}{5}x=17\ \ \ \ \ |multiply\ both\ sides\ by\ \frac{5}{12}\\\\x=\frac{85}{12}\\\\\boxed{x=7\frac{1}{12}}[/tex]
[tex]\frac{3}{4} * (\frac{4}{5x}-2) = \frac{11}{4} \ we \ bring \ to \ the \ same \ denominator \ in \ (...) \\ \frac{3}{4} * \frac{4-10x}{5x} = \frac{11}{4} <=> \frac{12-30x}{20x}= \frac{11}{4} <=> \\ 4(12-30x)=220x <=> 48 -120x =220x <=> \\ -120x-220x= -48 <=> -340x = - 48 |-1 <=> \\ x= \frac{48}{340}= 0,14[/tex]
